Solving Literal Equations
Given that x, y, and z are nonzero real numbers, solve the following equation for z: 3x2 -(4 - y) + 3z = 0.
A
z= -(3x^2 + y -4) / 3
B
z= -(3x^2 + y -4) / 6
C
z= -(3x^2 - y + 4) / 3
D
None of the above
E
z= 3x^2 + y -4 / 3
Question Leaderboard
Not enough data yet to show leaderboard.